青云英语翻译

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翻译结果1翻译结果2 翻译结果3翻译结果4翻译结果5

翻译结果1复制译文编辑译文朗读译文返回顶部

Data for the calculation of the linear least squares method, it will be x (t) = x0 * exp (rt) on both sides of the logarithm lnx (t) = lnx0 * exp (rt), lnx (t) = lnx0 + rt other y-= lnx (t) = lnx0, so we can get y = rt + a.

翻译结果2复制译文编辑译文朗读译文返回顶部

正在翻译,请等待...

翻译结果3复制译文编辑译文朗读译文返回顶部

For linear least squares calculations with data so as x (t) =x0*exp (RT) take the logarithm on both sides available lnx (t) =lnx0*exp (RT), lnx (t) =lnx0+RT, y=lnx (t), a=lnx0, available y=RT+a.

翻译结果4复制译文编辑译文朗读译文返回顶部

In order to use the smallest data for line 2, the calculation of the multiplication will be x (t) = x * EXP 0 (RT) both sides can be a logarithmic lnx (T) = lnx0 * exp(RT), lnx (T) = lnx0 + RT, and the other y = lnx (T) = lnx, a 0, so you can get a Y = RT+.

翻译结果5复制译文编辑译文朗读译文返回顶部

In order to carries on the linear least squares method with the data the computation, therefore nearby two takes x(t)=x0*exp(rt) the logarithm to be possible to result in lnx(t)=lnx0*exp(rt), lnx(t)=lnx0+rt, another y=lnx(t), a= lnx0, therefore may result in y= rt+a.
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