青云英语翻译

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翻译结果1翻译结果2 翻译结果3翻译结果4翻译结果5

翻译结果1复制译文编辑译文朗读译文返回顶部

能碰上一些硬开关条件

翻译结果2复制译文编辑译文朗读译文返回顶部

可以碰到一些困难转换条件

翻译结果3复制译文编辑译文朗读译文返回顶部

可以运行到一些硬开关的条件

翻译结果4复制译文编辑译文朗读译文返回顶部

正在翻译,请等待...

翻译结果5复制译文编辑译文朗读译文返回顶部

能跑入一些坚硬开关情况
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avest 背心 [translate] 
agranitgr 开始 [translate] 
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aWhere Annotations Can Be Used 那里可以使用注释 [translate] 
a3. Use Geometer's Sketchpad to show that the three medians of a triangle (the lines from the vertices to the midpoints of the opposite sides) all meet in one point. 3. 使用几何学家的草图表示,线从端点到 (反面中点全部在一点中遇见) 三角的三个中点。 [translate] 
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a   In order to study the influence of the vibration displacement and the vibration frequency of piezoelectric element on power performance, orthogonal experiments were carried out on these two factors.The factors and levels as shown in table 1, according to the experimental arrangements and achieved the experimental da 为了学习振动位移的影响和压电元素振动频率在力量表现,正交实验在这二个因素被执行。如表2所显示,因素和水平如表1所显示,根据实验性安排和达到800振动倍实验性数据。 [translate] 
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a  For lower Cd contentFigs.3c and 3d, emission from well layer dominates in the PL spectrum and emission from the defects and barriers are extremely weak, which implies that the perfectly smooth interfaces between well and barrier layer have been achieved in this SQW. Thus, most photon-generated carriers in the Zn 为更低的CD的美满的 Figs.3  c 和3  d ,放射从好的层数在PL光谱控制,并且放射从瑕疵和障碍是极端微弱的,暗示完全光滑的接口之间很好和障碍层在这SQW达到了。 因此,多数光子引起的载体在ZnO障碍水平放松入ZnCdO好的水平,导致强的放射从好的层数。 另一方面,低温宽度这QW放射是一样小的象48兆伏特。 这价值在飞机青玉基体增长的可比较的结构QWs大约三次小于由分子束外延。 更加宽广的PL行距从更加高级的Cd SQW起因于不同类扩展由于更大的构成波动和被贬低的好的层数质量和接口。 如上所述, CdO假设岩石盐结构,与ZnO不同纤锌矿结构。 更高的CD的内容井层成长以高水 [translate] 
a两辆 两辆 [translate] 
aBecause triangles BEF and AC are similar, and since BE is half of BA, it follows that EF is half of AC. Also, because triangles DHK and DAC are similar and DH is half of DA, it follows that HK is half of AC. Therefore HK = EF and triangles DEF and DHK are congruent. (Why?) Therefore ED = DF = FC, and the intersection D 由于三角BEF和AC是相似的和,因为是一半BA, EF一半AC的它跟随。 并且,因为三角DHK和DAC是相似的,并且DH是一半DA,它跟随HK是一半AC。 所以HK = EF和三角DEF和DHK是一致的。 (为什么?) 所以ED = DF = FC和二个中点的交叉点D是距离的三分之二从端点C的到反面的中点E。 点D也是距离的三分之二从端点A的到中点它的反面F。 从AF和铈是所有对中点,它跟随,如果我们画三角的第三中间BG,它必须相交AF在方式的点三分之二从A到F,即,在点D。 因此我们的结果被证明。 [translate] 
arigid high voltage 刚性高压 [translate] 
ato the applause of a bookish public 正在翻译,请等待... [translate] 
acan run into some hard switching conditions 能跑入一些坚硬开关情况 [translate]