青云英语翻译

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翻译结果1翻译结果2 翻译结果3翻译结果4翻译结果5

翻译结果1复制译文编辑译文朗读译文返回顶部

第一行中,r = 0时不偏移。 nb的​​移位相关(r,nb等)字节,其中的移位值移位相关(r,nb等)上的行数取决于底部的三个行循环移位,并且在等式(5.4)中给出的(见5.1.2节),具体地,InvShiftRows变换()变换过程如下:遥控移位ŕNB NB RCSS,',(())模为0

翻译结果2复制译文编辑译文朗读译文返回顶部

正在翻译,请等待...

翻译结果3复制译文编辑译文朗读译文返回顶部

第一行,r = 0,将不会调整。底部三行周期性格向 Nb shift(r,Nb) 个字节,转移价值 shift(r,Nb) 取决于行数,而鉴于方程 (5.4) 中 (请参阅秒 5.1.2)。具体来说,InvShiftRows() 转换收益,如下所示: r c shift Nb Nb r r c s,',((,)) mod for 0 < r < 4 和 0 c < Nb (5.8) 图 13 显示了 InvShiftRows() 转型。

翻译结果4复制译文编辑译文朗读译文返回顶部

第一行中,R=0,不移。 底部的三行都是循环移位NB shift(R,NB)字节,其中的偏移值偏移(R,NB)取决于行号,并在公式(5.4)(请参阅SEC。 5.1).具体而言,invshiftrows()转型收益,如下所示:r C Shift R NB笔记本电脑r C S S,`',(())mod for0

翻译结果5复制译文编辑译文朗读译文返回顶部

第一列, r = 0,没有被转移。 底下三列周期地由Nb (r, Nb)的转移字节在式(5.4)转移,转移价值转移(r, Nb)取决于列数字和被给(看秒。 5.1.2)。具体地, InvShiftRows ()变革进行如下: r c转移r Nb Nb r c s s, ‘((,)) mod为0 < r < 4和0c < Nb (5.8)图13说明InvShiftRows ()变革。
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aThe first row, r = 0, is not shifted. The bottom three rows are cyclically shifted by Nb shift(r,Nb) bytes, where the shift value shift(r,Nb) depends on the row number, and is given in equation (5.4) (see Sec. 5.1.2).Specifically, the InvShiftRows() transformation proceeds as follows: r c shift r Nb Nb r c s s ,',( ( 第一列, r = 0,没有被转移。 底下三列周期地由Nb (r, Nb)的转移字节在式(5.4)转移,转移价值转移(r, Nb)取决于列数字和被给(看秒。 5.1.2)。具体地, InvShiftRows ()变革进行如下: r c转移r Nb Nb r c s s, ‘((,)) mod为0 < r < 4和0c < Nb (5.8)图13说明InvShiftRows ()变革。 [translate]